Angular speed of a wheel is increased from 1200 rpm to 3120 rpm in 16 seconds.

Angular speed of a wheel is increased from 1200 rpm to 3120 rpm in 16 seconds. (i) What is the angular acceleration (Assume the acceleration is uniform)? (ii) How many revolution does the wheel make during this time?

Posted by: - Sanna
Posting Time: - 7/18/2015 1:25:49 PM
Subject: - Physics

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Best 5 Answers:-

Answer by:- Bruce

initial angular velocity, w1 = 1200 rpm = 1200*2pi/60 = 40 pi rad/s
Final angular velocity, w2 = 3120 rpm = 3120*2pi / 60 = 104 pi rad/s
Time t = 16 s
(i)Angular acceleration, a = (104-40)/16 = 64pi/16 = 4 pi rad/s^2
(ii) Angle, theta = 40pi*16 + ½*4pi * 256 = 1152pi rad
Thus, number of revolutions, n= 1152pi/2pi revolutions
= 576 rev

 
   

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