From a uniform disc of radius R, a circular disc of radius R/2 is cut out. The

From a uniform disc of radius R, a circular disc of radius R/2 is cut out. The center of the hole is at R/2 from the center of original disc. Locate the center of gravity of the resultant flat body.

Posted by: - Jason
Posting Time: - 7/18/2015 1:23:59 PM
Subject: - Physics

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Best 5 Answers:-

Answer by:- Zeuse

Let the mass of the disc = M
Therefore, the mass of the removed part of disc, m = (M/R^2)*(R/2)^2 = M/4
Now the center of gravity of the resulting flat body,
R= [M*0 – (M/4)*(R/2)]/(M-M/4)
= -(MR/8)/(3M/4)
= -R/6
Negative sign shows that the center of gravity lies at opposite direction of the original COM at a distance R/6.

 
   

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